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x^2-4.2x+2.1=0
a = 1; b = -4.2; c = +2.1;
Δ = b2-4ac
Δ = -4.22-4·1·2.1
Δ = 9.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4.2)-\sqrt{9.24}}{2*1}=\frac{4.2-\sqrt{9.24}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4.2)+\sqrt{9.24}}{2*1}=\frac{4.2+\sqrt{9.24}}{2} $
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